When pound-for-pound king Floyd Mayweather Jr. steps into the ring on May 2 to face Manny Pacquiao (57-5-2, 38 KO’s), the 11-time world champion will boast a 1½-inch height advantage over his Filipin rival.
Standing 5-feet 8-inches, 1996 Olympics bronze medalist Mayweather sports a 72-inch reach and comes to the fight defending an unblemished record of 47-0 with 26 stoppages by way of KO.
Mayweather, who began his professional boxing career in 1996 as a 130-pound super featherweight and has progressively moved up to the 154-pound super welterweight division, rates within the average boxer range for his weight.
Tony Pep, a canadian Mayweather fought as a super featherweight in 1998 stood at a towering 6-feet 1½-inches and had fought as a 125-pound featherweight early in his career.
Watch how Mayweather handled the long reach of Tony Pep:
On the other end of the spectrum is 5-foot 4-inch Argentine Carlos Alberto Ramon Rios, who challenged Mayweather for his WBC World super featherweight title in 1999.
The May 2 “Fight of the Century” will be fought with a 147-pound welterweight limit.